Respuesta :

We have the following:

[tex]\frac{2-y}{4+y}+\frac{3(y+2)}{y}[/tex]

replacing, y =2:

[tex]\begin{gathered} \frac{2-2}{4+2}+\frac{3(2+2)}{2} \\ \frac{0}{6}+\frac{3\cdot4}{2} \\ 0+\frac{12}{2}=6 \end{gathered}[/tex]

the answer is 6, the second option

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