We will have:
[tex]8i+5-2i=3i+23[/tex]We will operate like terms and solve for i, that is:
[tex]8i-2i-3i=23-5\Rightarrow3i=18\Rightarrow i=6[/tex]*Step by step:
[tex]8i+5-2i=3i+23\Rightarrow6i+5=3i+23[/tex][tex]\Rightarrow6i+5-5=3i+23-5\Rightarrow6i=3i+18[/tex][tex]\Rightarrow6i-3i=3i+18-3i\Rightarrow3i=18[/tex][tex]\Rightarrow\frac{3}{3}i=\frac{18}{3}\Rightarrow i=6[/tex]