Given:
The point (3,5)
The slope is 6.
To find the equation of the line:
Using the point-slope formula,
[tex]y-y_1=m(x-x_1)[/tex]
Substituting the point and slope, we get
[tex]\begin{gathered} y-5=6(x-3) \\ y-5=6x-18 \\ y=6x-18+5 \\ y=6x-13 \\ y-6x+13=0 \end{gathered}[/tex]
Hence, the equation of the line is,
[tex]y-6x+13=0[/tex]
