If A and B are independent events, then:
[tex]P(A\cap B)=P(A)\cdot P(B)[/tex]Then, we have:
[tex]\begin{gathered} P\mleft(A\mright)=\frac{3}{4} \\ P\mleft(B\mright)=\frac{1}{3} \\ P(A\cap B)=P(A)\cdot P(B) \\ P(A\cap B)=\frac{3}{4}\cdot\frac{1}{3} \\ \boldsymbol{P(A\cap B)=\frac{1}{4}} \end{gathered}[/tex]Therefore, if A and B are independent events, the probability of their
