We are asked to solve this logarithm, so, firstly, we factor the number 12 as (4)(3) in order to apply the property that states that the logarithm of a product is the sum of the logarithms. Therefore:
[tex]\log_4(12)=\log_4((4)(3))\text{ --> }\log_4(4)+\log_4(3)=1+\log_4(3)=1+0.79=1.79[/tex]
Therefore, the correct answer is A
