Respuesta :

rainbowdash8142
−3=−x+√​−2(x−3)​−3=−x+√​2(x−3)​​​ı−3+x=ı√​2(x−3)​​​
(x−3)​2​​=−2(x−3)6x​2​​−6x+9=−2x+6x​2​​−6x+9+2x−6=0x​2​​−4x+9−6=0x​2​​−4x+3=0(x−3)(x−1)=0x=3,1x=3

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-3 = -x + √(-2x + 6)
Squaring both sides, 
9 = -x² - 2x + 6
x² + 2x + 3 = 0
x² -x + 3x + 3 = 0
-x(x + 1) 3(x + 1)
(3 - x) (x + 1) = 0
x = 3 or -1

Hope this helps!