Respuesta :

[tex]\bf f(x)=\boxed{y}=2\boxed{x}-10\qquad inverse\implies =\boxed{x}=2\boxed{y}-10\impliedby f^{-1} \\\\\\ x+10=2y\implies \cfrac{x+10}{2}=y\implies \cfrac{x}{2}+\cfrac{10}{2}=y \\\\\\ \cfrac{x}{2}+5=y=f^{-1}(x)[/tex]

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