y = -2(x + 3)^2 - 4
First expand the parentheses:-
y = -2(x + 3)(x + 3) - 4
y = -2 [(x(x + 3) + 3(x + 3)] - 4
y = -2 ( x^2 + 3x + 3x + 9) - 4
y = -2(x^2 + 6x + 9) - 4
Now distribute the -2 over the parentheses:-
y = -2x^2 - 12x - 18 - 4
y = -2x^2 - 12x - 22 Answer
