what is the vertex of the quadratic function: y=-3(x+5)^2-4

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02-10-2017
Mathematics

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what is the vertex of the quadratic function: y=-3(x+5)^2-4

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WickedNightmare WickedNightmare · Answer 1 · 2017-10-02T13:48:09+02:00

WickedNightmare WickedNightmare

02-10-2017

V=(-5,-4)
to find the vertex you use V=-b/2a
y=-3(x+5)^2-4
which then turns to
y=-3x^2-30x-79
a=-3
b=-30 x=30/2(-3)
x=30/-6
x=-5
plug x into the equation and solve for y =-3(-5)^2-30(-5)-79
y=-4
x=-5 y=-4 Vertex=(-5,-4)

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