Nekomancer7959 Nekomancer7959
  • 02-01-2018
  • Mathematics
contestada

The equation of the line is 3y+2x=12 . what is the slope of the line perpendicular to this equation?

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Hosein
Hosein Hosein
  • 02-01-2018
the slope
[tex] \frac{3}{2} [/tex]
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cher
cher cher
  • 05-01-2020

Hey there! :)

3y + 2x = 12

To find the slope of this equation, we must turn this into slope-intercept form. Slope-intercept form is very simply : y = mx + b ; where m = slope, b = y-intercept.

Our first step should be to subtract 2x from both sides.

3y + 2x - 2x = 12 - 2x

Simplify.

3y = -2x + 12

Then, divide both sides by 3 so that we could get y by itself (which is what we call isolated in the math world).

3y ÷ 3 = (-2x + 12) ÷ 3

Simplify.

y = -2/3x + 4

So, our slope is -2/3!

~hope I helped~

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