Answer:
Virtual, Upright and the same size
Explanation:
As we know for plane mirror we have
[tex]d_i = -d_0[/tex]
image distance is same as that of object distance but on opposite side of the mirror.
now for the magnification we have
[tex]m = -\frac{d_i}{d_0}[/tex]
[tex]m = +1[/tex]
since magnification is positive so it must be virtual and upright image and since the magnitude of magnification is exactly 1 so it must be of same size as that of object size
