Answer:
The volume of the container is [tex]56\ in^{3}[/tex]
Step-by-step explanation:
we know that
The volume of the figure is equal to
[tex]V=Bh[/tex]
where
B is the area of the base
h is the height of the figure
Let
[tex]h=4\ in[/tex]
Find the area of the base B
[tex]B=(4*4)-(1*2)=14\ in^{2}[/tex]
substitute
[tex]V=14*4=56\ in^{3}[/tex]
