Respuesta :

popalabdulqayou
 [tex]f(2)=a(2)^3+b(2)^2+c(2)+d=8a+4b+2c+d f'(2)=3(2)^2a+2b(2)+c=12a+4b+c f''(2)=12a+2b f'''(2)=6a 0=8a+4b+2c+d 0=12a+4b+c 0=12a+2b 0=6a [/tex] 
you need relative minimum inorder to get the coefficient give me that and I will send u answer.