We are going to use this formula :
Q = M*C*ΔT
when Q is the heat released by the material in J
and M is the mass in gram = 1600 g
C is the specific heat capacity of iron = 0.4494 J/g
and ΔT is the changing in temperature = 155 - 25 = 130 °C
So by substitution:
∴ Q = 1600 g * 0.4494 J/g * 130 °C
= 93475 J
∴ The amount of heat released in Joule = 93475 J
