Respuesta :

anonymous12345678901
Since there are 10 digits, and 3 cylinders we can find the possible amount of numerical codes by multiplying 10, 3 times

10*10*10=1000

There would be 1000 possible numerical codes

I hope this helps.. sorry if it’s confusing or anything
gmany

Step-by-step explanation:

If the numbers can be repeated, we have such numeric codes:

10 · 10 · 10 = 1,000

If the numbers can not be repeated, then we have such numeric codes:

10 · 9 · 8 = 720

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