Answer:
V = 3.89 L
Explanation:
Given data:
Mass of oxygen = 5.024 g
Temperature = 28°C (28+273 = 301 k)
Pressure = 0.988 atm
Volume occupy by oxygen = ?
Solution:
PV = nRT
We will calculate the number of moles;
Number of moles = mass/ molar mass
Number of moles = 5.024 g/ 32 g/mol
Number of moles = 0.157 mol
Now we will calculate the volume,
PV = nRT
V = nRT/P
V = 0.157 mol × 0,.0821 atm.L /mol.K × 301 K / 0.998 atm
V = 3.88 L / 0.998
V = 3.89 L
