Answer:
given
the sequences are;5,11,17,23
now we have difference between first series and second seris is 6
so,tn=a+(n_1)×d (where a=1stseries,n is the
termand d is diff betwn 1st
and 2nd series)
so,tn=5+(n_1)×6
=5+6n_6
=6n_1...........n th term
now;
t1=6×1_1=5
t2=6×2_1=11
t3=6×3_1=17
t4=6×4_1=23
therefore ; the nth term of the given sequence is ; 6th_1.
